You've done the problem the way calculus students hate to do it: solving the Riemann sum limit.

The quick way to do it is to realize that the limit describes an integral as a limit of Riemann sums. Specifically:

The 3/n tells you that the width of each of the rectangles and the inside of the summation shows the sampling points of the function.

The quick way to do it is to realize that the limit describes an integral as a limit of Riemann sums. Specifically:

The 3/n tells you that the width of each of the rectangles and the inside of the summation shows the sampling points of the function.

Thanks!

That'll save many minutes of time!

That'll save many minutes of time!

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