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Ideals and polynomials

Posted: Sun Oct 16, 2011 3:38 am
by Hom
-- the content was deleted --

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 3:53 am
by owlpride
(1) and (3):

$$1+ x^4 = (1+x^2)^2 \text{ (mod 2)}$$
$$1 + x^6 = (1+x^3)^2 \text{ (mod 2)}$$

(2) is not in the ideal because you cannot get an x by multiplying or adding/subtracting powers of x^2 and x^3.

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 4:18 am
by Hom
Thanks owlpride.

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 8:07 am
by talkloud
$$(1+x^2)^2\equiv 1 + 2x^2 + x^4 \pmod 2$$

Since $$2x^2$$ is a multiple of 2, it is congruent to zero mod 2, so you get $$1+x^4$$.

The elements $$x^2,x^3$$ work the same way in $$\mathbb{Z}/2\mathbb{Z}[x]$$ as they do for any other polynomial ring. The construction of $$R[x]$$ ensures that $$x$$ is never an element of $$R$$, so it will behave the same way regardless of the choice of $$R$$.

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 9:07 am
by Hom
That makes prefect sense to me now. Thank you so much for the explanation.

Btw, do you guys know any good problem sets/practices for abstract algebra and general topology? I really think they can get a beginner like me into thinking various problems and getting a better understanding. :D

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 9:19 am
by goombayao
You realize it is against the rules to post this question at all, right?

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 9:46 am
by Hom
goombayao wrote:You realize it is against the rules to post this question at all, right?
Sorry, I was not aware of that but I am now. I've removed the content.

Re: Ideals and polynomials

Posted: Sun Oct 16, 2011 5:02 pm
by miguel
^^tattle-tail. WHO CARES.