owlpride wrote:You mean continuous?
Any k > 1 will do. If you consider the straight line y = ax through the origin, then the limit of f(x,ax) as x ->0 along this line is 0 as long as 2k > 2.
blitzer6266 wrote:Nope. k=2/3 will make the limit at 0 not exist: If you go along y=x, the limit will be infinity, where as if you go along y=0, the limit will be zero (since the function is identically 0 along the x and y axis).
Users browsing this forum: No registered users and 5 guests