Need a little help please!!!!
Maximize the function f(x,y) =sqrt(x^2+y^2) subject to the constraints x+3y≤10,x≥0 and y≥0.
Maximization
Re: Maximization
Look up the lagrangian multiplier method.
Re: Maximization
You can just notice that the maximum is achieved when x+3y=10. Then just substitute x=10-3y in x^2+y^2 and maximize it in the interval y \in [0, 10/3]. Take a square root of the result and that's it.
Re: Maximization
First sketch the domain. It is a triangle in quarant I. Then you substitude the vertices into the given function. No need to try (0, 0) 'cause the function is bigger when x and y are getting bigger.
Re: Maximization
Spice girl, do you get f(10, 0) = 10 as an answer?
Re: Maximization
The function is simply the distance from the origin. Our domain is a triangle in the first quadrant, with the furthest vertex at (10,0). Thus, the answer is 10.