GRE 9367 #18
Posted: Sat Sep 26, 2009 4:13 pm
For problem #18, I can take the derivative of the sum ok, but then am stuck when it comes to actually figuring out what it converges to as n -> inf. Here's what I get for f':
$$$f'(x) = \sum_{n=0}^\infty (-1)^n (2n) x^{2n-1}$$$
Any help appreciated...thanks in advance! =)
$$$f'(x) = \sum_{n=0}^\infty (-1)^n (2n) x^{2n-1}$$$
Any help appreciated...thanks in advance! =)