The circles are centered at (2,1,3) and (-3,2,4), not (3,2,4).
Therefore the distance between the two centers is calculated using the distance formula viz., ((2+3)^2 + (1-2)^2 + (3-4)^2)^.5 which equates to the root of 26, which is roughly 5.
Now, the radii of the two spheres are 1 and 4 units, so the minimal distance should be (the root of 26 ) -(1+4) which is a very insignificant number.
The answer I am getting is A, not E.
lecherme wrote:the centres of two spheres are (2,1,3)and(3,2,4),the distance between these centres are ((2-3)^2+(1-2)^2+(3-4)^2)^(1/2)=root(3)<the plus of radiis of the spheres=1+2=3,so the relationship of these two spheres are intersectant,that is,if keep the spheres in one coordinate system of 3 dimension,there must be at least a meeting point of the spheres.so the distance between the two spheres is 0.
Users browsing this forum: dbwood and 4 guests