GRE 9367 Q36

Forum for the GRE subject test in mathematics.
nomis
Posts: 2
Joined: Wed Aug 21, 2013 8:33 am

GRE 9367 Q36

Postby nomis » Wed Aug 21, 2013 8:40 am

I think this one should be an easier one, but I can't seem to figure it out.

36. If F is a function such that, for all positive integers x and y F(x,1)=x+1, F(1,y)=2y, and F(x+1, y+1) = F( F(x, y+1), y), then F(2,2) =
a) 8
b) 7
c) 6
d) 5
e) 4

correct answer is D.

Thanks for your responses.

berkbelt
Posts: 15
Joined: Sun Jun 02, 2013 12:19 pm

Re: GRE 9367 Q36

Postby berkbelt » Wed Aug 21, 2013 10:18 am

F(2,2) = F(1+1,1+1) = F(F(1,1+1),1) = F(F(1,2),1) = F(4,1) = 5.

nomis
Posts: 2
Joined: Wed Aug 21, 2013 8:33 am

Re: GRE 9367 Q36

Postby nomis » Thu Aug 22, 2013 6:41 am

AH. Perfect. Thanks again.




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