Correct.my understanding was that since the set "A" contains each rational number, it must at least be equal to Q or more.
Correct.Can we deduce from the wording of the question that "A" may contain elements that are not in Q?
I just did it in the previous post, didn't I?Can you give a counterexample to option A. for a set which contains all elements in Q (and maybe more).
The set of all limit points of Q is R. In order to have all its limit points A must be R.Secondly, could you explain choice B.
jayre wrote:Sorry to pull up this old thread, but I'm just slightly confused about the answer. I understand why all the incorrect choices are incorrect, but I did not think that R was closed.
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